Finding the value for rejection region using some kind of table

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The discussion focuses on determining the cutoff rejection region using Z-tables in hypothesis testing. The example provided uses a sample size of 34, a sample mean (X-bar) of 10.3, and a standard deviation (s) of 3.1 to calculate a rejection region at a significance level of 0.01. The cutoff value, Z-alpha, is established as 2.326 for a right-tailed test, which is derived from the Z-table. Additionally, the p-value of 0.0072 is calculated to support the rejection of the null hypothesis (H0: µ ≤ 9).

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korr2221
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I'm lost no how to find the cutoff rejection region and which table to use?

This is an example,
Data

n 34
X-bar 10.3
s 3.1

98% Confidence Interval for µ is
10.3 ± 2.33 x 0.5316
= (9.0632 , 11.5368)

Hypothesis
H0: µ ≤ 9
H1: µ > 9

Tests Z-stat = 1.3 = 2.4452
Statistic 0.5316

Significance Level = 0.01

Rejection Region =
Tail = RIGHT
Cutt -Off = Z-alpha = 2.326
Decision = Reject H0

p-value = 0.0072

I understand how they reject H0, but I am lost how they got 2.326. I think it's in the Z-table but I'm not sure, can someone explain to me clearly. It would also help if you can tell me how to find 0.0072 for the p-value.
 
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I'm not sure how your Z table is set up - whether it gives only tail areas or cumulative probabilities.

If it gives tail areas (areas to the right of specific Z-values, do this: look through the AREAS for 0.01 - the associated Z-value will be 2.326

If your Z- table gives cumulative probabilities (areas of the form P(Z <=z)), look for the area that is closest to 0.99 (this is 1 - 0.01) - again, the Z-value should be 2.236.

Some tables only give the area between 0 and specified values of Z. If this is the case, look through the areas for the value closest to 0.49 - again, you should find Z = 2.236.
 

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