Finding Thevenins equivlant using his thereom and nortons

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SUMMARY

The discussion focuses on finding the Thevenin equivalent of a circuit using Thevenin's theorem and source transformations. The user successfully calculated the equivalent resistance as 1.499 ohms by replacing voltage sources with shorts and current sources with open circuits. To complete the process, they need to determine the open-circuit voltage across points A and B with all sources activated, which will yield the Thevenin equivalent voltage. The suggestion to use source transformations for simplification was also mentioned as a viable approach.

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monkeyhead
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Hi there,
See attached for original circuit.

Basically I need to find thevenins equivalent of the network.

My attempt:-
To find the resistor equivalent
First of all I replaced all voltage sources with shorts, and replaced all current sources with open circuits.

This left me with 16 ohm (10+6),24 ohm and, 1.777 all in parallel.

The sum of the resistors gives the equivalent resistance of 1.499 ohm.

Now this is the part where I don't know what to do next. Do I convert the circuit so the sources are voltage sources?

Any help or guidance most appreciated

Any guidance much appreciated!
 

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Hi, I suggest that you do the transformation so all the voltage sources and current sources can be unite into one. This is just a suggestion.Please correct me if I'm wrong. Thank you!
 
You need to find the open-circuit voltage across A and B with all the sources activated. This will be the Thevenin equivalent voltage.

I believe using source transformations would have also worked...
 

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