Finding triangle height without trigonometry

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View attachment 1801 My daughter was given this problem in an exam. She could not do it and was never given the solution. I can do the problem using trig but she has not been taught trig yet. She says that it can be done without trig using a more simple method that she doesn't know. Could somebody please explain how it could be done without using trig. It would be most appreciated :confused:
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Hello.

Lo that I think simplest is:

[tex]area=\dfrac{6*8}{2}=24[/tex]

By placing the right triangle to another position.

Then:

[tex]24=\dfrac{10*h}{2}[/tex]

[tex]h=4.8[/tex]

Regards.
 
Another method would be to use similarity.

$$\frac{h}{6}=\frac{8}{10}$$

$$h=\frac{48}{10}=4.8$$

or

$$\frac{h}{8}=\frac{6}{10}$$

$$h=\frac{48}{10}=4.8$$