Finding vector C perpendicular to A with dot product B·C = 19.0

[Kieran12]

Homework Statement

You are given vectors A⃗ = 4.8 i^− 6.4 j^ and B⃗ = - 3.6 i^+ 6.8 j^. A third vector C⃗ lies in the xy-plane. Vector C⃗ is perpendicular to vector A⃗ and the scalar product of C⃗ with B⃗ is 19.0.

Find the x -component of vector C⃗ .

Find the y-component of vector C⃗ .

Homework Equations

Dot Product
Cross Product

The Attempt at a Solution

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No idea where to start on this one really. I've plotted the A and B vectors on a graph and that's about as far as I;ve got.

Cheers everyone.

 

[RUber]

For A and C to be perpendicular, their dot product must equal zero. Try setting $C=x\hat i + y \hat j$ and satisfy the relations.
Otherwise, if you want to think in terms of lines, the perpendicular to a line with slope m has slope -1/m.