[First Year Statics] Replace Force System

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SUMMARY

The discussion centers on calculating the resultant force and moment in a statics problem involving a force system. The calculated force resultant is (100i + 620j + 800k) equating to 379 N, while the moment result is incorrectly stated as (100i - 620j + 800k) instead of the correct value of 590 N*m. The user attempted to compute the moment about point O using the cross product method but encountered discrepancies in their calculations, particularly with the vector (-3i + 2j), which was questioned by another participant as not being relevant to the forces present.

PREREQUISITES
  • Understanding of vector operations in three-dimensional space
  • Familiarity with cross product calculations
  • Knowledge of static equilibrium principles
  • Proficiency in resolving forces and moments in statics
NEXT STEPS
  • Review vector cross product calculations in three dimensions
  • Study the principles of static equilibrium in mechanics
  • Practice problems involving resultant forces and moments
  • Explore the application of force systems in engineering statics
USEFUL FOR

Students studying engineering mechanics, particularly those focusing on statics, as well as educators and tutors looking to clarify concepts related to force systems and moment calculations.

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Homework Statement


upload_2018-2-18_14-3-6.png

Homework Equations

The Attempt at a Solution


[/B]
the force resultant = (100i +620j +800k) = 379 N
moment result is (100i-620j+800k) = 1017 which is not correct!

I calculated the moment of all forces about point O using cross product so...

(-3i + 2j) x (-200j) + (-3i +2j) x (-400i) +(3i +0.5k) x (120i +160k)

But, somehow, I am not getting 590 N*m which is the correct answer
 

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Where are you getting (-3i + 2j)? There is no force present at that point
 

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