What is the Tension in the String Holding a Submerged Cork?

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Homework Help Overview

The problem involves calculating the tension in a string holding a cork submerged in water, with specific parameters such as depth, density of the cork, and volume provided. The context is within fluid mechanics and buoyancy principles.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the equilibrium of forces acting on the cork, including buoyant force and weight. There are attempts to apply the density and volume relationships to find the tension. Some participants question the unit conversions and calculations related to volume.

Discussion Status

Participants are actively engaging with the problem, identifying potential errors in unit conversion and discussing the implications of these errors on the calculations. There is no explicit consensus on the correct approach yet, but the conversation is exploring the necessary corrections.

Contextual Notes

There is a noted confusion regarding the conversion of volume from cubic centimeters to cubic meters, which affects the calculations. The original poster also mentions the presence of multiple choice answers that may not align with their calculations.

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Homework Statement


A cork is held at the bottom of a bucket of
water by a piece of string. The actual depth
of the cork is 0.713786 m below the surface of
the water.

If the density of the cork is 157 kg/m3
and the volume of the cork is 3 cm3
, then what is the tension in the string? The acceleration
of gravity is 9.8 m/s
2
. Assume the density of
water is 1000 kg/m3
.


Homework Equations


d= m/v Fb= weight of displaced fluid


The Attempt at a Solution


The tension should be the force required to keep it in equilibrium...
using d=m/v, into dv = m (1000)(0.03) = 30 kg (mass of displaced water)(9.8)
weight of displaced water = Fb = 294 N
using dv = m again for the cork. (157)(0.03) = 4.71 kg (9.8) = 46.158 N

294 - 46.158 = 247.842 N .
Its a multiple choice answer and the choices are either that number but the decimals in the wrong place (all the answers are smaller), or 0.0123921 N.
maybe I'm supposed to use the depth and P=pgh somehow if that other numbers right, but I'm not sure how it would apply to this problem.
 
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Units, Units, Units!

3 cm^3 is not the same as 0.03 m^3

You are essentially saying that 3 cc of water has a mass of 30 kg!
 
that makes sense... so it would be like (0.03)^3 then i guess
 
Looks like the problem setter didn't think of this particular mistake, or there would have been a choice to match.
 

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