Fluids-blow across top of straw to draw up olive oil

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SUMMARY

The discussion focuses on calculating the minimum airspeed required to draw olive oil upward through a straw by applying Bernoulli's principle. The relevant equation used is P1 + 0.5*density*v1^2 + density*g*y1 = P2 + 0.5*density*v2^2 + density*g*y2. The density of olive oil is specified as 920 kg/m³, and the calculated airspeed (v2) needed to achieve this is approximately 14.83 m/s. The participants clarify the pressure difference necessary to support the olive oil column and how to apply the equation correctly.

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Homework Statement



You try to remove olive oil from a glass by blowing across the top of a vertical straw immersed in the olive oil. What is the minimum speed you must give the air at the top of the straw to draw olive oil upward through a height of 1.5 cm?
(Note: The density of olive oil, if you need it is 920 kg per cubic meter.)

Homework Equations



P1 + .5*density*v1^2 + density*g*y1 = P2 + .5*density*v2^2 + density*g*y2


The Attempt at a Solution



P1 + .5*density*v1^2 + density*g*y1 = P2 + .5*density*v2^2 + density*g*y2
P1 = .5*density*v2^2 + density*g*y2
V2 = 14.83 m/s
V2 is close, but not right; I'm not sure how to find P2. What do I need to do different?
 
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I don't understand your calculations. How did you get from P1 = .5*density*v2^2 + density*g*y2 to v2=14.83 m/s?

You can calculate the pressure difference between the top and bottom of the straw that's needed to support the olive oil column; it's just rho*g*h. Then, you can apply the equation P1 + .5*density*v1^2 + density*g*y1 = P2 + .5*density*v2^2 + density*g*y2 with the left side representing the bottom of the straw and the right side representing the top. v1 would be 0, since the air at the bottom isn't moving, and you've just calculated P1-P2.
 

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