Hello,(adsbygoogle = window.adsbygoogle || []).push({});

I have a problem I've been trying to solve. I originally have vector AB. I know both vector A, vector B, and the angle between. They are on the same plane.

Now say I change the angle between the two vectors. They still remain the same magnitudes, and remain on the same plane. Assume vector A is fixed. How can I find the new updated vector B.

My attempt at a solution:

|A||B|cos theta = A*B

A, |B|, and theta are known

Equation 1)

|A||B|cos theta = axbx + ayby + azbz

Equation 2)

ax + by + cz = d

This is the equation of the plane that the vectors are located on.

My problem is I need one more equation to solve this. Maybe I am going about this the wrong way? Any help is appreciated.

Thanks,

AS

**Physics Forums - The Fusion of Science and Community**

# For vector AB, how to find vector B given vector A and the angle between

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: For vector AB, how to find vector B given vector A and the angle between

Loading...

**Physics Forums - The Fusion of Science and Community**