Force in crossbar of inverted A-frame suspended by two ropes

[Crazedkid]

hi i need help understanding what to do with the information that was given in the problem if u could point mein the right direction i would greatly appreciate it. thank you

An invered "A" is suspended from the ceiling by 2 vertical ropes. Each leg of the "A" has a length of 2L and a weight of 120.0N. The horizontal crossbar has a negligable weight. Find the force that the crossbar applies to each leg.
Known:
W=120.0N per leg
l of legs= 2L
angle at top of "A" = 60Degrees
l of crossbar=L

 

[Parth Dave]

I think the key idea here is that the system is in static equilibrium. That means that the net force and torque are zero. Can you take it from there?

 

[ultimatejester]

Parth Dave is right. The system is at rest so the net force is 0. If that is not the case read below.

the formula is W=Fcosd

but what doesn't make sense is that you don't have the displacement. Are you sure it says 2L not 2m.