A 700 kg elevator suspended by a cable accelerates upwards at 3 m/s^2. The force exerted by the cable on the elevator is?(adsbygoogle = window.adsbygoogle || []).push({});

(use g=10 m/s^2)

m=700 kg

a= 3.0 m/s^2

Fnet= 700 kg * 3.0 m/s^2

= 2,100.0 N Upward force

Fnet= 700 kg * 10 m/s^2

= 7,000.0 N Downward force

Fnet= 2,100.0 N + 7,000.0 N = 9,100.0 N

So is 9,100.0 N the total force exerted on the cable?

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# Homework Help: Force question on elevator cable

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