Force to push a 26-kg bobsled down a 4.1° incline to 70 km/h over 73 m

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Homework Statement


The coefficient of kinetic friction for a 26-kg bobsled on a track is 0.13. What force is required to push it down a 4.1° incline
and achieve a speed of 7.0E1.0 km/h at the end of 73 m?

Homework Equations


Force friction=F*k
v_f=v_0+a*t
x_f=x_0+v_0*t+0.5a*t^2
v_f^2=v_0^2+2*a(x_f-x_0)
x-x_0=[(v_0-v+v_f)/2]*2

And just sum of forces=0
F=ma

The Attempt at a Solution


I'm lost...
 
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Discussion

So this is two problems rolled up into one. On one hand you need to figure out what acceleration will let you reach a speed of 70 km/h after traveling 73 m, and then you will also need to figure out what force when summed against the frictional force will provide that acceleration.