Form 8 Digit Number with 7s, 6s & 0s

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harishm18
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main aim : You have to form a 8 digit number such that
the conditions are
the ones place stands no of 7's in the final 8 digit no that will form
the tens place stands : no of 6's in the final 8 digit no
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then the 10^7 the place stands for no of 0's in the 8 digit no



what is the no.?
 
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It has nly 6 digits
 
Lostinthought said:
It has nly 6 digits
Count again...
:smile:
 
What about a big number-factorial_of_a_number ?
:smile: