Form 8 Digit Number with 7s, 6s & 0s

  • Thread starter harishm18
  • Start date
In summary, the main aim is to form an 8 digit number that meets the following conditions: the ones place must equal the number of 7's in the final 8 digit number, the tens place must equal the number of 6's in the final 8 digit number, and the 10^7 place must equal the number of 0's in the 8 digit number. The final number must also have only 6 digits. It is important to clarify the use of "no" as both number and abbreviation for number.
  • #1
harishm18
5
0
main aim : You have to form a 8 digit number such that
the conditions are
the ones place stands no of 7's in the final 8 digit no that will form
the tens place stands : no of 6's in the final 8 digit no
...
...
...
then the 10^7 the place stands for no of 0's in the 8 digit no



what is the no.?
 
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  • #2
Your post is confusing because you're using no as number and no as no.

Perhaps you could clarify it a bit more.
 
  • #3
The way you word your riddles is a big no-no!
 
  • #4
42101000
:smile:
 
  • #5
It has nly 6 digits
 
  • #6
Lostinthought said:
It has nly 6 digits
Count again...
:smile:
 
  • #7
Borek said:
The way you word your riddles is a big no-no!

A big number-number?
 
  • #8
What about a big number-factorial_of_a_number ?
:smile:
 

FAQ: Form 8 Digit Number with 7s, 6s & 0s

1. How many different combinations can be made with 8 digits using only 7s, 6s, and 0s?

There are 3^8, or 6,561 different combinations that can be made with 8 digits using only 7s, 6s, and 0s.

2. What is the probability of getting a number that contains all 7s and 6s when creating an 8-digit number with only 7s, 6s, and 0s?

The probability of getting a number that contains all 7s and 6s is 1/3^8, or approximately 0.00000012.

3. How many 8-digit numbers can be created with exactly 4 7s and 4 6s?

There are 8!/(4!*4!), or 70 different 8-digit numbers that can be created with exactly 4 7s and 4 6s.

4. What is the largest possible 8-digit number that can be created with only 7s, 6s, and 0s?

The largest possible 8-digit number that can be created with only 7s, 6s, and 0s is 777,777,76.

5. Is there a pattern or formula for creating an 8-digit number with only 7s, 6s, and 0s?

Yes, there is a pattern. The first digit must be a 7 or 6, and the remaining 7 digits can be filled in with any combination of 7s, 6s, and 0s. This can be represented as (7 or 6)(7 or 6)(7 or 6)(7 or 6)(7 or 6)(7 or 6)(7 or 6)(7 or 6).

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