Formula for even and odd number multiplication

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SUMMARY

The forum discussion focuses on deriving the formulas for the multiplication of even and odd numbers. The product of even numbers from 2 to 100 can be expressed as f(n) = 2^n * n!, where n is the count of even numbers. For odd numbers, the product is represented as f(n) = (1 - 1/2)(3 - 1/2)(5 - 1/2)...((n - 1) - 1/2)(n - 1/2), which relates to the Gamma function. The discussion emphasizes the importance of these formulas in proving that the product of fractions 1/2 x 3/4 x 5/6 ... x 99/100 is less than 1/10.

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  • Familiarity with the Gamma function
  • Basic knowledge of even and odd number properties
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gaobo9109
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Can anyone tell me what's the formula for even and odd number multiplication.
For example, what would be the product for 2 x 4 x 6 x 8 x 10 ... x 100 and what would be the product for 1 x 3 x 5 x 7 x 9 x 12 ... x 99? I am trying to solve a problem which asks me to prove that 1/2 x 3/4 x 5/6 ... x 99/100 < 1/10. And i think finding the formula is key to solving this question.
 
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To find out the product of even numbers think of the factorial.

n!=1.2.3.4...(n-1)n

So you want to find the product

f(n)=2.4.6.8...(2(n-1))(2n)

Notice that this is just the normal factorial function but each number has been multiplied by 2. So it is 2^n bigger.

So it is

f(n)=2^nn! = 2.4.6.8...(2(n-1))(2n)

Next you want to find the product such that

f(n)=1.3.5.7...(2(n-1)-1)(2n-1)

Its similar... divide each one by 2 and

2^{-n}f(n)=\frac{1}{2}\frac{3}{2}\frac{5}{2}...\frac{2n-3}{2}\frac{n-1}{2}

2^{-n}f(n)=(1-\frac{1}{2})(3-\frac{1}{2})(5-\frac{1}{2})...((n-1)-\frac{1}{2})(n-\frac{1}{2})

(n-\frac{1}{2})!=(n-\frac{1}{2})(n-1-\frac{1}{2})...\frac{5}{2}\frac{3}{2}\frac{1}{2}\sqrt{\pi}

To work out why this is so look at the definition for the Gamma function.

\frac{2^n}{\sqrt{\pi}}(n-\frac{1}{2})! = 1.3.5.7...(2n-1)

So now you have the formula for both things
 

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