Frequency Spectrum of a Vibrating String

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SUMMARY

The discussion focuses on the frequency spectrum of a vibrating string, specifically analyzing the relationship between frequency and period. The period is defined as $\tau = \frac{2L}{c(n + \frac{1}{2})}$, leading to the frequency formula $f = \frac{c(n + \frac{1}{2})}{2L}$. Participants clarify the distinction between frequency and natural frequency (eigenfrequencies), with natural frequency relating to resonance in systems like mass-spring setups. The angular frequency is also discussed, represented as $\omega = 2\pi f$.

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  • Understanding of wave mechanics and harmonic functions
  • Familiarity with the concepts of frequency, period, and angular frequency
  • Basic knowledge of eigenfrequencies in mechanical systems
  • Mathematical proficiency in handling trigonometric functions and series
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  • Study the derivation of eigenfrequencies in vibrating systems
  • Explore the concept of resonance in forced oscillations
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Physicists, mechanical engineers, and students studying wave mechanics or oscillatory systems will benefit from this discussion, particularly those interested in the mathematical modeling of vibrations and resonance phenomena.

Dustinsfl
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Given $\sin\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right]$.

The period is $\tau = \frac{2L}{c\left(n + \frac{1}{2}\right)}$ so the frequency is $\frac{1}{\tau}$, correct?
 
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Yes:

$\displaystyle f=\frac{1}{\tau}$
 
MarkFL said:
Yes:

$\displaystyle f=\frac{1}{\tau}$

Is the period I obtained correct? Is that the yes or is the yes it is the reciprocal?
 
If you have a function $\sin(kt)$, find the period $\tau$ by setting $k\tau=2\pi$.
 
Sorry for being vague. :)

I agree with the period you found and with the relationship between frequency and period that you stated.

$\displaystyle \tau=\frac{2\pi}{\omega}$

In your case $\displaystyle \omega=\frac{\pi e}{L}\left(n+\frac{1}{2} \right)$

And so:

$\displaystyle \tau=\frac{2\pi}{ \frac{\pi e}{L} \left(n+ \frac{1}{2} \right)}= \frac{2L}{e\left(n+\frac{1}{2} \right)}$
 
Ackbach said:
If you have a function $\sin(kt)$, find the period $\tau$ by setting $k\tau=2\pi$.
Is there a difference between frequency and natural frequency (eigenfrequencies)?
 
dwsmith said:
Is there a difference between frequency and natural frequency (eigenfrequencies)?

The term "natural frequency" refers to resonance. So if you have a forced mass-spring system, e.g., and you tune the forcing function to the same frequency as a term in the homogeneous solution, you end up with unstable behavior.

The term "frequency" just refers to what's going on in this thread.

There's also the term "angular frequency", which is represented by $\omega=2\pi f$.

Hope that's as clear as mud.
 
Ackbach said:
The term "natural frequency" refers to resonance. So if you have a forced mass-spring system, e.g., and you tune the forcing function to the same frequency as a term in the homogeneous solution, you end up with unstable behavior.

The term "frequency" just refers to what's going on in this thread.

There's also the term "angular frequency", which is represented by $\omega=2\pi f$.

Hope that's as clear as mud.

I am trying to find the natural frequency (eigenfrequency) of $u$.
How would I do that then?
$$
u(x,t) = \sum_{n = 1}^{\infty}\sin\left[\frac{\pi x}{L}\left(n + \frac{1}{2}\right)\right]\left\{A_n\cos\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right] + B_n\sin\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right]\right\}
$$
 
dwsmith said:
I am trying to find the natural frequency (eigenfrequency) of $u$.
How would I do that then?
$$
u(x,t) = \sum_{n = 1}^{\infty}\sin\left[\frac{\pi x}{L}\left(n + \frac{1}{2}\right)\right]\left\{A_n\cos\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right] + B_n\sin\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right]\right\}
$$

Well, I could be wrong, but I would say that all of your
$$f_{n}=\frac{c\left(n + \frac{1}{2}\right)}{2L}$$
are the eigenfrequencies. I don't think there's one single eigenfrequency.
 

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