Full equation for acidified KMnO4 reacting with KI

[new hand]

I want to ask what is the full equation of acidified potassium permanganate and potassium iodide?

I have worked out the ionic equation...

2 MnO4- + 16 H+ + 10I- --> 2Mn2+ + 8H2O + 5I2-

How to write the full equation??

THanks

 

[Borek]

There is a typo - "-" at the end of the reaction equation (but otherwise it is OK).

How to write the full equation??

I don't think it is always possible (and actually rarely matters). In general - add counterions on the left side to make the solution electrically neutral (so start with KMnO₄, HCl and KI), copy counterions on the right, try to pair them with anions on the right.

 

[war485]

Your equation isn't balanced.
Can you work out its half-reactions?

 

[Borek]

Your equation isn't balanced.

It is balanced, it just contains a typo.

If it is not balanced - please tell us what is wrong.

 

[war485]

ah yes sorry, it is balanced when the - on I2 is removed. I have nothing more to add.