Fundamental Group of (X,p): D^2\{(x,0) : 0<=x<=1}

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Discussion Overview

The discussion revolves around the fundamental group of the space \( D^2 \setminus \{(x,0) : 0 \leq x \leq 1\} \) at the point \( p = (-1,0) \). Participants explore the properties of fundamental groups, particularly in relation to homotopy and the construction of isomorphisms between the fundamental groups of product spaces.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant questions whether the fundamental group of the specified space is trivial, suggesting that all loops based at \( p \) are homotopic.
  • Another participant agrees and provides a homotopy argument using a straight-line homotopy to demonstrate that any loop can be continuously deformed to a constant loop at \( p \).
  • A different participant shifts the focus to the isomorphism of fundamental groups for product spaces, expressing a desire to construct this isomorphism.
  • A subsequent reply proposes a method to construct the isomorphism by combining loops from each space and projecting paths onto the respective components.

Areas of Agreement / Disagreement

There is agreement on the triviality of the fundamental group for the specified space, but the discussion on constructing the isomorphism for product spaces remains exploratory, with no consensus on the best approach.

Contextual Notes

The discussion includes assumptions about the properties of the spaces involved and the nature of homotopies, which may not be universally applicable without further context.

Who May Find This Useful

Participants interested in algebraic topology, particularly in the study of fundamental groups and their properties in relation to homotopy and product spaces.

Mikemaths
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I am doing some revision and trying to do fundamental groups and I was wondering if the fundamental group of the following space is {1} i.e. all loops based p are homotopic.

fundamental group of (X,p) = D^2\{(x,0) : 0<=x<=1} where p=(-1,0)
 
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Yes. Just consider a loop f : [0,1] \to X. This is homotopic to the constant map c(t)=p by the usual straight-line homotopy (t,i) \mapsto (1-i)f(t) + ip. You can verify yourself that this works.

The intuitive idea when dealing with fairly nice subsets of \mathbb{R}^2 is that the fundamental group is trivial if and only if the space has no holes (since then you can wrap a loop around that hole).
 
Ok thanks I get that as I thought.

I am trying to show that the fundamental group of a product of Topological Spaces is isomorphic to the product of fundamental groups:

pi1(X x Y , (p,q)) -> pi1(X,p) x pi1(Y,q)

I can understand this but want to construct the isomorphism and am struggling?
 
Just construct it in the obvious way. Given two loops f_1 : I \to X and f_2 : I \to Y you can construct a path I \to X \times Y where t \mapsto (f_1(t),f_2(t)). Conversely given a path f : I \to X \times Y you can construct paths I \to X and I \to Y by projecting onto X and Y. You can show that both of these give homomorphisms of the fundamental groups and that they are inverses.
 

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