Geodesics on Surfaces: Proving the Relationship to Particle Motion

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SUMMARY

The discussion centers on proving that a particle constrained to move on a surface defined by the equation f(x,y,z)=0, with no external forces acting on it, follows the geodesic of that surface. The geodesic is derived from the integral expression involving the speed v, which remains constant due to the absence of forces. The participants are exploring the relationship between the geodesic path and the path derived from the Lagrangian mechanics, specifically using the Euler-Lagrange equations to establish the connection.

PREREQUISITES
  • Understanding of differential geometry, specifically geodesics on surfaces.
  • Familiarity with Lagrangian mechanics and the Euler-Lagrange equations.
  • Knowledge of calculus, particularly integrals and derivatives in multiple dimensions.
  • Basic concepts of particle motion in physics, including the principles of motion without external forces.
NEXT STEPS
  • Study the derivation of geodesics in differential geometry.
  • Learn how to apply the Euler-Lagrange equations in classical mechanics.
  • Explore the implications of constant speed in particle motion on curved surfaces.
  • Investigate the relationship between Lagrangian mechanics and geometric interpretations of motion.
USEFUL FOR

Students of physics and mathematics, particularly those focusing on classical mechanics and differential geometry, as well as researchers interested in the mathematical foundations of particle motion on surfaces.

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Homework Statement


Prove that a particle constrained to move on a surface f(x,y,z)=0 and subject to no forces, moves along the geodesic of the surface.


Homework Equations





The Attempt at a Solution


OK, we should prove that the path the particle takes and the geodesic are given by the same expression.

For the geodesic:
\int dt=\int\frac{ds}{v}=\int\frac{\sqrt{dx^2+dy^2+dz^2}}{v}
v must be constant since there are no forces - components of v may change along the path, but the speed will remain the same.

Now for the path:
\frac{d}{dt}\frac{\partial L}{\partial \dot{x}}=\frac{\partial L}{\partial x}
etc.

But where from now on??
 
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Anyone with an idea?
 

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