Geometry Problem: Find Overlapping Area

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SUMMARY

The problem involves finding the overlapping area of two congruent triangles formed by cutting a 12cm by 6cm card along its diagonal. The solution requires drawing a line segment from the right angle to the intersection of the hypotenuses, resulting in four smaller triangles of equal area. Consequently, the area of the overlapping region is determined to be 2/3 of the area of one of the original triangles, which is a straightforward geometric approach without the use of coordinates or angles.

PREREQUISITES
  • Understanding of basic geometric principles, specifically triangle properties.
  • Familiarity with area calculations for triangles.
  • Knowledge of congruence in geometric shapes.
  • Ability to visualize geometric arrangements without coordinate systems.
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  • Study the properties of congruent triangles in geometry.
  • Learn how to calculate the area of triangles using different methods.
  • Explore geometric proofs involving overlapping shapes.
  • Investigate the concept of geometric transformations and their applications.
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Students studying geometry, educators teaching geometric concepts, and anyone interested in solving geometric problems involving area and congruence.

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I can't get this problem... no idea how to do it. Can't use coordinates / angles, just straightforward geometry. (by angles I mean, you can't use a calculator to find em, then do everything from there)

Any help appreciated... thanks

"A card 12cm long and 6 cm wide is cut along a diagonal to form two congruent triangles. The triangles are arranged as shown. Find the area of the region where the triangles overlap."

http://img314.imageshack.us/img314/7241/untitled8ew.gif
 
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Draw a line segment from the right angle to the intersection of the two hypotenuses. You now have four small triangles. It should be evident (i.e. you should be able to prove) that all four triangles have the same area. It follows that the area of the overlap region is 2/3 the area of one of the original triangles.
 
Nice solution!
 

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