Given order for every element in a symmetric group

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SUMMARY

The discussion focuses on computing the order of elements in the symmetric group S4. Participants confirm that the most efficient method involves using cycle decomposition, particularly by examining representatives from each conjugacy class. The order of elements is consistent within each conjugacy class, allowing for simplification in calculations. The decomposition of S4 into A4 and other groups is also mentioned as a structural approach to understanding the group.

PREREQUISITES
  • Understanding of symmetric groups, specifically S4
  • Knowledge of cycle decomposition in group theory
  • Familiarity with conjugacy classes in group theory
  • Basic concepts of group homomorphisms and semidirect products
NEXT STEPS
  • Study cycle decomposition techniques in symmetric groups
  • Learn about conjugacy classes in Sn for various n
  • Explore the structure of alternating groups, particularly A4
  • Investigate the properties of semidirect products in group theory
USEFUL FOR

Mathematicians, students of abstract algebra, and anyone interested in group theory, particularly those studying symmetric groups and their properties.

Mr Davis 97
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Compute the order of each of the elements in the symmetric group ##S_4##.

Is the best way to do this just to write out each element's cycle decomposition, or is there a more efficient way?
 
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Since the order of the elements are the same within each conjugacy class, I would just take one representative of each conjugacy class. But yes, I would do it by looking at the cycles of that representative.
 
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Mr Davis 97 said:
Compute the order of each of the elements in the symmetric group ##S_4##.

Is the best way to do this just to write out each element's cycle decomposition, or is there a more efficient way?
You can decompose the group:
$$S_4 \cong A_4 \rtimes \mathbb{Z}_2 \cong (V_4 \rtimes \mathbb{Z_3}) \rtimes \mathbb{Z}_2 \cong (\mathbb{Z}_2^2 \rtimes \mathbb{Z_3}) \rtimes \mathbb{Z}_2$$
 

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