Golf ball kinetic energy at highest point and at 8.47 m below

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eanderson
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A 47.7-g golf ball is driven from the tee with an initial speed of 55.4 m/s and rises to a height of 31.2 m. (a) Neglect air resistance and determine the kinetic energy of the ball at its highest point. (b) What is its speed when it is 8.47 m below its highest point?
 
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What have you tried? You need to show some effort. What equations/concepts might apply here?
 
K = (1/2)mv^2 and i need something to help deal with the height part
 
U=mgh... 47.7(-9.8)31.2 =14584.754 = U or gravitational potential energy
 
Mechanical energy (KE + PE) is conserved. Careful with units. (The mass is given in grams, not kg.)
 
wouldnt kinetic be 0 at the highest point because all the energy is potential?
 
eanderson said:
wouldnt kinetic be 0 at the highest point because all the energy is potential?
No. Only the vertical component of velocity is zero at the highest point--it's still moving horizontally.
 
eanderson said:
what do i do now?
Compare the initial energy (KE + PE) at the start with the energy (KE + PE) at the top. The ball loses KE as it gains PE.