Graphing y = -2 + sin(θ/3 - π/12)

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iRaid
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Homework Statement


[itex]y=-2+sin((\frac{\Theta}{3})-(\frac{\pi}{12}))[/itex]


Homework Equations




The Attempt at a Solution


[PLAIN]http://img715.imageshack.us/img715/7707/trigg.png

Phase shift: [itex]\frac{\pi}{4}[/itex]
Vertical shift: -2
Period: [itex]6\pi[/itex]
 
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iRaid said:

Homework Statement


[itex]y=-2+sin((\frac{\Theta}{3})-(\frac{\pi}{12}))[/itex]


Homework Equations




The Attempt at a Solution


[PLAIN]http://img715.imageshack.us/img715/7707/trigg.png

Phase shift: [itex]\frac{\pi}{4}[/itex]
Vertical shift: -2
Period: [itex]6\pi[/itex]

Your graph is incorrect. When θ = 7π/4, y = -2 + sin(7π/12 - π/12) = -2 + sin(π/2) = -2 + 1 = -1. Your graph shows a y value of -2, not -1.

I think you might have done the stretch and phase shift in the wrong order, or maybe you did them in the right order but did your graph wrong.
 
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Oh wow I misinterpreted it as a cosine graph (starting at high point rather than mid point).. Thank you.