Solve cos(θ + π/2) if sin θ = 3/7 Exactly

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Homework Help Overview

The problem involves evaluating cos(θ + π/2) given that sin θ = 3/7. The context is trigonometry, specifically focusing on the relationships between sine and cosine functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the possibility of using a right-angled triangle to find cos θ based on the given sine value. There are suggestions to expand cos(θ + π/2) and to consider known trigonometric identities.

Discussion Status

Some participants have offered insights into the relationship between sine and cosine, noting that cos(θ + π/2) can be expressed in terms of sin θ. There is an acknowledgment of different approaches being explored, including graphical methods and triangle representation.

Contextual Notes

Participants mention constraints such as time limitations for memorizing equations and the need for exact evaluations rather than approximate calculations.

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Homework Statement



Evaluate cos(θ + π/2) if sin θ = 3/7, exactly.

Homework Equations



How do I go about doing this exactly instead of approximately on the calculator?

The Attempt at a Solution



The only way I know how to do it is taking the inverse sin of 3/7 and adding 90 degrees and taking the cos of that result.

Thank you for your time!
 
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If sin θ = 3/7 and sin θ = opposite/hypotenuse, can you draw a right angled triangle, with an angle θ, with the opposite side as 3 and the hypotenuse as 7 and find what cosθ is?

What do you get when you expand out cos(θ + π/2)?

EDIT: expand out cos(θ + π/2) first and then see what quantities you need to find.
 
Wow, way easier than I was letting it be. Thank you!
 
Or use the fact that [tex]cos(\theta+\pi/2)=-sin\theta[/tex]

edit: you would probably realize this after expanding the cosine, but if you didn't know how to, using the known graphs of cosx and sinx can give you that result easily.
 
I appreciate the reference there Mentallic! The issue I'm having is, unfortunately, a lack of time to memorize certain equations and equivalents for an exam.
 
Oh yes of course I never expected you to remember this result. I didn't even have this memorised, I had to graph [itex]cos(x+\pi/2)[/itex] to see what it was equivalent to.
 
Haha, that makes me feel a little better :P
 

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