Gravitational Potential Energy of 75-kg Pilot at 1.2 km Height

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SUMMARY

The gravitational potential energy (GPE) of a 75-kg pilot at a height of 1.2 km is calculated using the formula GPE = mgh, where m is mass, g is the acceleration due to gravity (approximately 9.81 m/s²), and h is height. In this case, the GPE is 75 kg * 9.81 m/s² * 1200 m, resulting in a value of 882,900 Joules. The phrase "compared to the plane" indicates that the potential energy is measured relative to the plane's height, which is considered zero at the moment of the jump.

PREREQUISITES
  • Understanding of gravitational potential energy calculations
  • Familiarity with the formula GPE = mgh
  • Knowledge of units of measurement (Joules, kilograms, meters)
  • Basic physics concepts related to mass and gravity
NEXT STEPS
  • Study the derivation and applications of the gravitational potential energy formula
  • Learn about energy conservation principles in physics
  • Explore the effects of height on potential energy in different gravitational fields
  • Investigate real-world applications of gravitational potential energy in aerospace engineering
USEFUL FOR

Physics students, educators, aerospace engineers, and anyone interested in understanding gravitational potential energy and its implications in real-world scenarios.

pinkyjoshi65
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A 75-kg pilot jumps from a damaged plane at a height of 1.2 km. At the instant he leaves the plane, what is his gravitational potential energy compared to the plane?

So i know how to do the problem, but I am cofused because of the words "compared to the plane". Does that mean that the h is 0?
 
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It could be -it's not a well worded question.
 

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