Gravitational redshift and black holes

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SUMMARY

Gravitational redshift affects light attempting to escape a black hole by causing it to lose energy, resulting in a longer wavelength as observed from a distance. This phenomenon is fundamentally explained by the Equivalence Principle, which states that the laws of physics in a local inertial frame align with those of special relativity. The discussion highlights the importance of reference frames in understanding gravitational effects, particularly in scenarios involving free-falling objects and emitted photons.

PREREQUISITES
  • Understanding of the Equivalence Principle in general relativity
  • Familiarity with the concept of gravitational fields
  • Basic knowledge of photon behavior in physics
  • Awareness of reference frames in physics
NEXT STEPS
  • Research the implications of the Equivalence Principle in general relativity
  • Study the concept of gravitational fields and their effects on light
  • Explore the phenomenon of redshift in various astrophysical contexts
  • Investigate the weak field approximation in gravitational physics
USEFUL FOR

Astrophysicists, physics students, and anyone interested in the effects of gravity on light and the behavior of black holes.

niin
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Questions: Gravitational redshift and black holes

I have some questions:

1. What does gravitational redshift do to light trying to escape a black hole? Is the light destroyed?

2. And what is the physical cause of this redshift? (I’m not interested in equations and math, only the physical cause).

I hope someone can help me. Thanks.
 
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The beginning to understand gravitational redshift is the Equivalence Principle.

"In a local inertial frame the laws of physics are given by the laws of special relativity"

Now we have to reference frames S1 and S2, S1 situated at some distance above S2.
They are in a gravitational field.
S1 will always remain still and S2 will start free falling at t=0.

At t=0 we emit a photon from the origin to S2 towards S1.

... this continues but some math are required.

you can work out the frequency that S1 will receive if you use the weak field approximation.
 
Kuon,
I don't see why the "equivalence principle" should solve it. If you think of the first reference frame as being accelerated, then there is no redshift, because both reference frame must be accelerated or the distance would change between them. And it's not the distance that changes in this case. Right?
 

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