Gravity: Why Objects Fall at Same Rate?

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All objects fall at the same rate due to the balance between gravitational force and inertia. While a more massive object exerts a greater gravitational force, it also has greater inertia, which requires more force to accelerate. This means that the increased weight of a heavier object is countered by its resistance to motion, resulting in the same acceleration for all objects in free fall. The acceleration due to gravity remains constant at approximately 9.81 m/s² near the Earth's surface. Thus, regardless of mass, all objects fall at the same rate when air resistance is negligible.
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What I've been trying to figure out recently is: I understand that all objects fall at the same rate but don't understand how this makes sense given that things weigh different amounts. For instance, if I were to have a large person sit on my chest they would press much harder against me because of gravity than a small child, leading me to believe that the more massive adult is displaying more gravitational "force", but they fall at the same rate? Why?
 
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Jorge610 said:
What I've been trying to figure out recently is: I understand that all objects fall at the same rate but don't understand how this makes sense given that things weigh different amounts. For instance, if I were to have a large person sit on my chest they would press much harder against me because of gravity than a small child, leading me to believe that the more massive adult is displaying more gravitational "force", but they fall at the same rate? Why?

Because a more massive object takes more to accelerate it to the same speed as a less massive object.

The extra pull is exactly balanced by the extra inertia to not move.


Another way to look at it. Forget about gravity for a moment. Turn the experiment on its side. If you attached ropes to a small obejct and to a large object, and then pulled on them, would you expect the more massive object to leap towards you faster than the less massive object?
 
I think it's more like this

(GmM)/(r*r) = ma

cancel out the little m (say its the mas of the falling object)
and we have the gravitational constant times the mass of the earth, divided by the distance from its center, squared, as the acceleration of gravity. on most of earth, that's 9.81. :)
 
Jorge610 said:
What I've been trying to figure out recently is: I understand that all objects fall at the same rate but don't understand how this makes sense given that things weigh different amounts. For instance, if I were to have a large person sit on my chest they would press much harder against me because of gravity than a small child, leading me to believe that the more massive adult is displaying more gravitational "force", but they fall at the same rate? Why?

Please read an entry in the FAQ thread in the General Physics forum.

Dave has given you a very good "intuitive" reason why this occurs. While a larger mass may have a larger weight, it also has a larger inertia. So the greater force it has just about cancels the larger force one needs to move a heavier object by the same rate.

Zz.
 
I do not have a good working knowledge of physics yet. I tried to piece this together but after researching this, I couldn’t figure out the correct laws of physics to combine to develop a formula to answer this question. Ex. 1 - A moving object impacts a static object at a constant velocity. Ex. 2 - A moving object impacts a static object at the same velocity but is accelerating at the moment of impact. Assuming the mass of the objects is the same and the velocity at the moment of impact...

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