Green's function for the wave function

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SUMMARY

The discussion focuses on solving the time-dependent Schrödinger equation using Green's functions. The equation \(H\Psi = i\hbar\frac{\partial \Psi}{\partial t}\) is transformed into a Green's function equation \((H-i\hbar\frac{\partial }{\partial t})G(t,t_{0}) \Psi(t_{0}) = -i\hbar\delta(t-t_{0})\). The transition from this equation to the final wave function solution \(\Psi(t) = G(t,t_{0})\Psi(t_{0})\) requires the condition that \(G(t,t_0) = 0\) for \(t < t_0\) and \(G(t,t_0) \to 1\) as \(t \to t_0^+\). This process ensures that the solution satisfies the Schrödinger equation correctly.

PREREQUISITES
  • Understanding of the time-dependent Schrödinger equation
  • Familiarity with Green's functions in quantum mechanics
  • Knowledge of delta functions and their properties
  • Basic concepts of boundary conditions in differential equations
NEXT STEPS
  • Study the derivation of Green's functions in quantum mechanics
  • Explore the implications of boundary conditions on differential equations
  • Read section 7.2.1 of the referenced book for one-dimensional ODE applications
  • Investigate the role of delta functions in quantum mechanics and their applications
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Students and researchers in quantum mechanics, physicists working with wave functions, and anyone interested in advanced mathematical techniques in physics.

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We want to solve the equation.
$$H\Psi = i\hbar\frac{\partial \Psi}{\partial t} $$ (1)

If we solve the following equation for G

$$(H-i\hbar\frac{\partial }{\partial t})G(t,t_{0}) \Psi(t_{0}) = -i\hbar\delta(t-t_{0})$$ (2)

The final solution for our wave function is,

$$\Psi(t) = G(t,t_{0})\Psi(t_{0})$$ (3)I don't understand the steps. How do we get from (2) to (3) ?
 
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First: (2) is not the differential equation for the Green's function, you need to remove the ##\Psi(t_0)##.

Second: The differential equation on its own does not specify the Green's function, you need to add the condition that ##G(t,t_0) = 0## for ##t < t_0##. This will imply that ##G(t,t_0) \to 1## as ##t \to t_0^+##. With that, you will find that (3) satisfies the Schrödinger equation with ##\Psi(t) \to \Psi(t_0)## as ##t \to t_0^+##.

If you have access to my book, this is discussed in section 7.2.1 for a one-dimensional ODE, but it generalises directly to your case.
 
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