Calculating Apparent Weight of a Solid Immersed in a Liquid | Homework Help"

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Homework Help Overview

The discussion revolves around calculating the apparent weight of a solid with a given density when it is fully immersed in a liquid of a different density. The original poster presents a scenario involving a solid weighing 0.5 kg in air and seeks assistance in determining its apparent weight in a liquid with a density of 8000 kg/m³.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants question the units used for weight, noting that weight should be expressed in Newtons rather than kilograms. There is also discussion about the distinction between weight and mass, with some participants suggesting that the original poster may be conflating the two terms. Additionally, there are inquiries about the graphing of data related to a ball dropping, with suggestions about the nature of the graph and assumptions regarding air resistance.

Discussion Status

The conversation includes various interpretations of the original poster's question, with some participants attempting to clarify the terminology used. There is a mix of focus on the apparent weight calculation and the graphing of motion, indicating that multiple lines of inquiry are being explored. Some participants express confusion about the original question and acknowledge misunderstandings.

Contextual Notes

There is a noted confusion regarding the use of units for weight and mass, as well as the implications of the solid being completely submerged in the liquid. Participants are also grappling with the relevance of graphing in relation to the original problem.

gautam_physics
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hi


confusing
a solid of density 5000 kg m-3(m raised to 3) weighs 0.5 kg in air
it is completely immersed in a a liquid in a liqiud of density 8000 kg m-3(m raised to three) .
calculate apparent weight of solid in the liqiud

please help as soon as possible
i got to do ma homework
bye

P.S help meeeeeeee:eek: :rolleyes:
 
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hmm...weight is suppose to be in Newton but urs is in kilogram??
 
I need help with graphing!

semc said:
hmm...weight is suppose to be in Newton but urs is in kilogram??


Um.. can you guys help me? I need to know what the graph would look like if I'm graphing the data for a ball droping downwards...
 
Would the slope be going down and would the heights be negative on the graph?
 
hmm...weight is suppose to be in Newton but urs is in kilogram??

Weight is often used synonymously with mass so obviously he is meaning the weight of the object to be the mass of the object. Making the distinction between those two terms is a bit pedantic...AZ_Physics could you maybe shed some light on what information you have at your disposal? I need to know what you are plotting on each axis. Is it speed as a function of the distance from the point of release?
 
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big man said:
Weight is often used synonymously with mass so obviously he is meaning the weight of the object to be the mass of the object. Making the distinction between those two terms is a bit pedantic...

I hope you're not for real, since making the distinction between the terms 'weight' and 'mass' is of essential meaning for anyone who even wants to deal with the letter 'p' of the word 'physics'. :smile:
 
Yes I am for real radou. I probably said it the wrong way though. I meant it's pedantic here in the 'intro to physics'. It's not to say that it isn't important to make the distinction, but when you're dealing with people who do a physics course as just an 'extra' I don't see it as the main point that should be made.

I mean that statement really came across as a smartarse statement. It just said that weight should be in Newtons. It didn't provide him any help or clearly point out that mass is different to weight. So I really wanted to point out that he wasn't being helpful at all.
 
[Edit]
I misunderstood the comments. Forget it.
 
Last edited by a moderator:
:blushing: :blushing: :blushing: oops my bad.

I completely misread that question. I thought it was an issue of finding the mass of the submerged part of the object.But it says it is completely submerged. I'm not thinking straight at all tonight. This is pathetic haha.
 
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  • #10
AZ_Physics said:
Um.. can you guys help me? I need to know what the graph would look like if I'm graphing the data for a ball droping downwards...

if you are talking about the v-t graph, assume air resistance is neligible when falling in air, the graph would be y=x until a certain t before it becomes a straight line.for the object falling in liquid, it will be something like a log graph but tends to terminal velocity faster. hope that this helps.
big man said:
I mean that statement really came across as a smartarse statement. It just said that weight should be in Newtons. It didn't provide him any help or clearly point out that mass is different to weight. So I really wanted to point out that he wasn't being helpful at all.
i was trying to know what his 0.5 is referring to...:frown:
 
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