According to [tex]<x|H|x\prime>=(-\hbar ^2 /2m \frac{\partial^2 }{\partial x^2}+v(x)) \delta (x-x\prime)[/tex] can one draw the conclusion that the Hamiltonian is always diagonal in the position basis?(adsbygoogle = window.adsbygoogle || []).push({});

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# Hamiltonian in the position basis

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