Hamiltonian of a Physical Theory: Lagrangian vs Transformation

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SUMMARY

The discussion centers on the relationship between Hamiltonian and Lagrangian formulations in physical theories, specifically addressing the application of the Legendre transform. It is established that the Legendre transform is essential for deriving the Hamiltonian from the Lagrangian, but it requires the Lagrangian to be a convex function of the time derivative of generalized coordinates. A specific example illustrating this relationship is requested, highlighting the necessity of the Legendre transform's existence for successful conversion between the two formulations.

PREREQUISITES
  • Understanding of Lagrangian mechanics
  • Familiarity with Hamiltonian mechanics
  • Knowledge of the Legendre transform
  • Concept of convex functions in mathematics
NEXT STEPS
  • Study the Legendre transform in detail
  • Explore examples of Lagrangian to Hamiltonian transformations
  • Investigate conditions for convexity in Lagrangian functions
  • Review the implications of Hamiltonian mechanics in physical theories
USEFUL FOR

Physicists, students of theoretical mechanics, and anyone interested in the mathematical foundations of classical mechanics will benefit from this discussion.

Narasoma
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What does it means for a physical theory to have hamiltonian, if it is formulated in lagrangian form? Why doesn't someone just apply the lagrangian transformation to the theory, and therefore its hamiltonian is automatically gotten?
 
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Can you be more specific and give a specific example?

In general, you can get to the Hamiltonian formulation of the same theory by applying the Legendre transform (which is what I assume that you mean) to your Lagrangian. In order for this to work, the Legendre transform needs to exist, which in turn requires the Lagrangian to be a convex function of the time derivative of your generalised coordinates.
 
Orodruin said:
Can you be more specific and give a specific example?

In general, you can get to the Hamiltonian formulation of the same theory by applying the Legendre transform (which is what I assume that you mean) to your Lagrangian. In order for this to work, the Legendre transform needs to exist, which in turn requires the Lagrangian to be a convex function of the time derivative of your generalised coordinates.
Ah, sorry. Legendre transformation. That was what I meant. But doesn't it always exist?
 
Narasoma said:
Ah, sorry. Legendre transformation. That was what I meant. But doesn't it always exist?
No. See the wikipedia page.
 

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