Have a pretty basic chem problem about lights and radiation

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An instrument can detect 9450 photons of light of wavelength of 8.065 × 10^-8 m. What is the minimum amount of energy in J to which the instrument is sensitive? Express answer in scientific notation..

i have tried to use the e = (planck's constant) ( speed of light ) / (wavelenghth) but i am not sure how the photons figure is used
 
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If one photon carries 10-18 J of energy, how much energy is carried by two identical photons?
 
where did you get 10^-18
 
Nowhere, it is not directly related to the question. I could as well ask "If one photon carries 1018 J of energy, how much energy is carried by two identical photons?", although that'll be quite a photon :bugeye:
 
so how would i know how much energy does each photon carry
 
You have already listed equation that allows calculation of the energy of a single photon.
 
so would i plug the wavelength into the equation and multiply by the number of photons and get my answer?