# Having trouble with this one anyone can give some insight?

1. Sep 11, 2015

### james0001

1. The problem statement, all variables and given/known data
During an all-night cram session, a student heats up a 0.360 liter (0.360 x 10- 3 m3) glass (Pyrex) beaker of cold coffee. Initially, the temperature is 18.1 °C, and the beaker is filled to the brim. A short time later when the student returns, the temperature has risen to 94.6 °C. The coefficient of volume expansion of coffee is the same as that of water. How much coffee (in cubic meters) has spilled out of the beaker?

2. Relevant equations

dV = V0 â (t1 - t0)

therefore

0.00036*0.000214(of water?)(94.6-18.1)
=
dV = V1 - V0 = change in volume

is this the correct equation?
3. The attempt at a solution

2. Sep 11, 2015

### BvU

And what is the coefficient of expansion for Pyrex glass ?

3. Sep 11, 2015

### james0001

4.0(10-6 m/(m K))*)

4. Sep 11, 2015

### BvU

Which means it can be ignored and your approach is imho a good start.
Now I look at the value for â (usually the volumetric expansion coefficient is denoted with the symbol $\beta$) and compare with the table here .
Notice something ? Where does your value come from ?

By the way, I forgot:

Hello James, and welcome to PF !

Last edited: Sep 11, 2015