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Having trouble with this one anyone can give some insight?

  1. Sep 11, 2015 #1
    1. The problem statement, all variables and given/known data
    During an all-night cram session, a student heats up a 0.360 liter (0.360 x 10- 3 m3) glass (Pyrex) beaker of cold coffee. Initially, the temperature is 18.1 °C, and the beaker is filled to the brim. A short time later when the student returns, the temperature has risen to 94.6 °C. The coefficient of volume expansion of coffee is the same as that of water. How much coffee (in cubic meters) has spilled out of the beaker?


    2. Relevant equations

    dV = V0 â (t1 - t0)

    therefore

    0.00036*0.000214(of water?)(94.6-18.1)
    =
    dV = V1 - V0 = change in volume

    = answer

    is this the correct equation?
    3. The attempt at a solution
     
  2. jcsd
  3. Sep 11, 2015 #2

    BvU

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    And what is the coefficient of expansion for Pyrex glass ?
     
  4. Sep 11, 2015 #3
    4.0(10-6 m/(m K))*)
     
  5. Sep 11, 2015 #4

    BvU

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    Which means it can be ignored and your approach is imho a good start.
    Now I look at the value for â (usually the volumetric expansion coefficient is denoted with the symbol ##\beta##) and compare with the table here .
    Notice something ? Where does your value come from ?

    By the way, I forgot:

    Hello James, and welcome to PF :smile: !
     
    Last edited: Sep 11, 2015
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