He+ Energy Level Diagram: Interaction Effects?

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Discussion Overview

The discussion revolves around the energy level diagram of singly ionized helium (He+), specifically addressing the influence of the orbital angular quantum number (l) and the interactions of the remaining electron. Participants explore whether to consider the effects of the second electron's absence on the energy levels and how this relates to the hydrogen atom model.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions whether to include the interaction of the "outside" electron when drawing the energy level diagram for He+, suggesting that the effect of l on energy levels is contingent on electron interactions.
  • Another participant asserts that for singly ionized helium, the energy levels resemble those of an isolated hydrogen atom, with the main difference being the reduced mass correction.
  • A follow-up response seeks confirmation that the second quantum number (l) does not affect the energy levels of He+, implying that it behaves like a single-electron atom.
  • Another participant clarifies that for excited states of He+, there is no effect on n and l, reinforcing the hydrogen-like nature of the ion and mentioning additional structures such as fine structure and Lamb shifts.

Areas of Agreement / Disagreement

Participants express differing views on the relevance of the orbital angular quantum number (l) in the context of He+. While some suggest it has no effect due to the single-electron nature, others discuss the implications of fine structure and other corrections, indicating that the discussion remains unresolved.

Contextual Notes

There are assumptions regarding the treatment of electron interactions and the applicability of hydrogen-like models to He+. The discussion does not resolve the implications of these assumptions on the energy level diagram.

MonsieurWise
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For drawing a energy level diagram of He+ (singly ionized He), do I draw it without the interaction of the "outside" electron, thus no effect of orbital angular quantum number l (because there's only 1 electron left). Or should I draw it with the interaction with the "outside" electron, leading to the effect the orbital angular quantum number l make on the energy level? Because if I'm not wrong, the effect of l on energy levels is based on electron interaction, right? (I'm trying to draw an energy diagram explaining the spectrum of Helium)
 
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If it is singly ionized helium, with only one electron bound in any quantum state, then the energy levels are like an isolated hydrogen atom with a doubly-charged proton, except that the reduced mass correction is less. This is a gas molecule, so it is not close to a loose electron or to other molecules in a solid or liquid.
 
Thank you, so there will be no effect of the 2nd quantum number on the energy level of He+, right?
Thanks!
 
If you mean for the He+ ion excited states, that there is no effect on n and l ( l <= n-1), it is a single-electron atom and should be hydrogen-like. So it has both fine structure and hyperfine structure, Lamb shifts, etc..
 

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