Height of pine tree casting shadow on a wall

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chawki
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Homework Statement


The sun was shining in the yard of engineer Jack Smith. Jack was reading in the shadow cast by the pine tree planted by his grandfather Tom Smith. The length of the horizontal part of the shadow was 6.0 m and the height of the vertical part of the shadow on the wall was 3.6 m. The height angle of the rays of the sun was 42degrees.

Homework Equations


Find the height of the pine tree.



The Attempt at a Solution


Is it 5.4m!
 
hi chawki! :smile:
chawki said:
The length of the horizontal part of the shadow was 6.0 m and the height of the vertical part of the shadow on the wall was 3.6 m. The height angle of the rays of the sun was 42degrees.

read the question :rolleyes: …

the shadow goes along the ground and up the wall :wink:
 


Yes, i think I'm right...
we have Tan 42 = h/6
so h= 5.4m
tell me if I'm wrong
 
if the height was only 5.4, the shadow would only just reach the wall, and not go up it
 
have you drawn a diagram?

a diagram is essential for solving questions like this

describe to us what your diagram looks like (including the wall) :smile:
 


Here it is
 
Attachments
  • Diagram of a sun ray grazing the top of a tree and reaching a wall; the horizontal distance from the tree to the wall is labelled 6.0 m and the wall height is labelled 3.6 m.
    new.JPG
    10.8 KB · Views: 479
hmm … when i said that a diagram is essential, i rather assumed that you would also draw in the right-angled triangle that you're using …

how else does the diagram help? :redface:​

(nice tree, btw :smile: … though shouldn't it be taller, for 42° ? :wink:)
 


i'm not sure, it is hard :(
i sent you a graph as i found it...
 
Attachments
  • Diagram of a sun's ray at 42 degrees striking a tree and a house wall, with a 3.6 m height marked on the wall and a 6.0 m horizontal distance labelled Jack from the tree base.
    new.JPG
    11.4 KB · Views: 502
ah, now i see what you're doing wrong …

to use tan42°, you need a right-angled triangle, but you've drawn a sort of four-sided triangle :rolleyes:

for the good old three-sided triangle that your professor is expecting you to come up with, you need to draw a horizontal line from the top of that arrow (up the wall) to the tree …

try that! :smile:​

(because the little circle you've drawn to show 42° should be at a point, shouldn't it, not a big line? :wink:)
 


WHAT HORIZONTAL LINE...
Can you draw it...and send it to me...i will understand it by my own
 
this line …
tiny-tim said:
… you need to draw a horizontal line from the top of that arrow (up the wall) to the tree …

try that! :smile:​
 


Right...after smoking and drinking big cup of coffee...i found out what you wanted to say..
Tan42 = 3.6/x
so: x=4
and then:
Tan42 =h/(6+4)
h=9m ?
 
Attachments
  • Diagram of a sun at upper left with a ray passing over a small tree of height h, a 6.0 m horizontal distance marked Jack, and a house wall at right with a 3.6 m vertical mark, angle 42 at the ground, and distance x labeled along the base.
    new.JPG
    12.8 KB · Views: 482
yes! :biggrin:

(though i'd just have drawn the smaller triangle, found its height was 5.4, added it to the height of the shadow, and got 9.0 that way :wink:)

ok, now you see the importance of a good diagram, and of being willing to draw extra lines on it? :smile:​
 


:D all i needed is a cup of coffee LOL
Thank you again :)
 
chawki said:
:D all i needed is a cup of coffee LOL

then give up smoking! :wink: o:)
 


Thanks guys, I found reading this thread thoroughly entertaining! Big-ups to both of you..