Helicity of the positron in zero mass limit

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SUMMARY

The discussion confirms that in the massless limit, positrons exhibit the same helicity as antineutrinos due to their shared SU(2) doublet status. It is established that helicity operators commute with SU(2) generators, leading to the decoupling of left-handed and right-handed fermion components. Right-handed fermions, including positrons in this limit, couple only to the neutral weak current and form weak isospin singlets, while left-handed fermions couple to the charged weak current and form weak isospin doublets. The conversation clarifies that both right- and left-handed states of positrons and electrons persist even in the massless limit.

PREREQUISITES
  • Understanding of SU(2) gauge theory
  • Familiarity with weak isospin and weak currents
  • Knowledge of helicity and its significance in particle physics
  • Concept of massless particles and their interactions
NEXT STEPS
  • Research the implications of SU(2) symmetry in particle interactions
  • Study the role of the Higgs field in mass generation for fermions
  • Examine the properties of left-handed and right-handed neutrinos and antineutrinos
  • Explore the behavior of massless charged particles in high-energy physics
USEFUL FOR

Particle physicists, theoretical physicists, and students studying the Standard Model of particle physics will benefit from this discussion, particularly those interested in the properties of fermions and their interactions in the massless limit.

Sphysicist
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Hi...

I read somewhere that positron, in the massless, limit will have the same helicity as the antineutrino.

This must be because they are in the same SU(2) doublet.

So helicity operator must commute with the SU(2) generators.

Please confirm.
 
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What happens in the massless limit is that the left-handed and right-handed components of a fermion decouple from each other. Right-handed fermions couple only to the neutral weak current (Z meson) and electromagnetic current, and form weak isospin singlets. Left-handed fermions couple as well to the charged weak current (W meson) and form weak isospin doublets.
 
Thanks...I understand that...

Now, antineutrinos are right-handed...so positrons also will be right-handed in the mass-less limit, since the electrons will be left-handed...

It is observed in nature that neutrinos are left-handed and anti-neutrinos are right-handed..
It is also true that the neutrinos have SU(2)_L interactions...so the antineutrinos have an SU(2)_R, right?

How do we know that, when we turn off masses, electrons won't end up being all right-handed?
 
so positrons also will be right-handed in the mass-less limit, since the electrons will be left-handed...
No. There will still exist both right- and left-handed positrons and electrons. What I said was, in the massless limit the right- and left-handed states decouple from each other.

Right-handed electrons (And left-handed positrons) are SU2 singlets. They do not interact with the charged weak current, but they do interact with neutral currents. For this reason they can still be created in reactions. (Didn't I say this already? :smile:)

By "massless limit", you could mean either "imagine the coupling constant to the Higgs field is zero", or "high energy limit where the mass is negligible". Some people get uncomfortable talking about massless charged particles. But note two things: Such concerns would apply equally to both right- and left-handed fermions. And, electrons nearly are massless charged particles already!
 

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