HELP Calculating contact angle of benzene.

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SUMMARY

The discussion focuses on calculating the contact angle of benzene when it wets glass, using specific measurements from a capillary tube experiment. The benzene rose 1.71 mm and water rose 4.90 mm at 20.0°C, with known densities of 0.879 g/cm³ for benzene and 0.998 g/cm³ for water. The surface tensions provided are 2.89 × 10^-2 N/m for benzene and 7.28 × 10^-2 N/m for water. The contact angle for water is assumed to be zero, and the equation used for calculation is y1 = cosθ + y1,2 - y2 = 0.

PREREQUISITES
  • Understanding of capillary action and its relation to contact angle
  • Familiarity with surface tension concepts and measurements
  • Knowledge of basic fluid mechanics principles
  • Ability to manipulate and solve algebraic equations
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  • Research the method for calculating contact angles using the Young-Laplace equation
  • Learn about the impact of surface tension on capillary rise in different liquids
  • Explore experimental techniques for measuring surface tension
  • Investigate the relationship between contact angle and wettability in materials science
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Chemistry students, materials scientists, and researchers interested in fluid dynamics and surface interactions will benefit from this discussion.

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Homework Statement



In an experiment to determine how well benzene wets glass, benzene was found to rise to 1.71 mm in a certain capillary tube at 20.0 C. In the same tube, water rose 4.90 mm at 20.0 C. Calculate the contact angle for benzene, give that at 20.0 C, benzene = 0.879 gcm^-3, pwater = 0.998 gcm^-3, benzene = 2.89 * 10^-2 Nm^-1 and ywater = 7.28 * 10^-2 Nm^-1. The contact angle for water is assumed to be theta = 0.

Homework Equations


y1 = cosθ + y1,2 - y2 = 0


The Attempt at a Solution



I don't know where to start. I know y1 can be found by finding the capillary radius of water and using that for benzene. But how do you find y1,2 and y2? Aren't they surface tensions of the solid glass surface which is not given?
 
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At first glance, and without working it on paper - can't you calculate them from the information about water?
 

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