- #1

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- Thread starter erogol
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- #1

- 14

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- #2

tiny-tim

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Hi erogol!

Show us what you've tried, and where you're stuck, and then we'll know how to help!

- #3

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- 0

i have no sense to solve it i just know answer is 2^(2n-1) + 2^n -1

- #4

tiny-tim

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i have no sense to solve it i just know answer is 2^(2n-1) + 2^n -1

ok, start by making a sum over all possible (even) numbers of 0s …

the total number of legitimated words is ∑ what ?

- #5

HallsofIvy

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So you are not even going to try?

- #6

tiny-tim

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