- #1
NotaPhysicsMan
- 146
- 0
Ok the question is:
A resistor (resistance=R) is connected first in parallel and then in series with a 2.00 ohm resistor. A battery delivers five times as much current to the parallel combination as it does the series combination. Determine the two possible values for R.
So let's see: I can use I=V/R
For series it's I=V/(R+2)
For parallel it's 5I=V/(1/R+1/2ohm) Ok, now I equate the Currents (I)
and I get V/(R+2)=V/5(1/R+1/2). I can cancel out the V's and I'll have:
Now I solve for R?
Am I on the right track?
A resistor (resistance=R) is connected first in parallel and then in series with a 2.00 ohm resistor. A battery delivers five times as much current to the parallel combination as it does the series combination. Determine the two possible values for R.
So let's see: I can use I=V/R
For series it's I=V/(R+2)
For parallel it's 5I=V/(1/R+1/2ohm) Ok, now I equate the Currents (I)
and I get V/(R+2)=V/5(1/R+1/2). I can cancel out the V's and I'll have:
Now I solve for R?
Am I on the right track?