2) A Uniform Boars has a mass of 1.5kg and length of 100cm, Note the Weight is negligible. A) Where should it be supported so that it will balance a 10g mass places at an end, a 60kg mass on the other end, and a 40kg mass placed 30 cm to the 10g mass? The answer should be 0.511m a. First you need to convert all g to kg and cm to m Therefore, (10g)(1X10-3kg1g) = 0,010kg (40g)(1X10-3kg/1g) = 0.040kg (60g)(1X10-3kg/1g) = 0.060kg (30cm)(1X10-2m/1cm) = 0.30m (100cm)(1x10-2m/1cm) = 1.0m (0cm)(1x10-2m/1cm)= 0 m Using the center of mass equation you get Xcg = W1X1 + W2X2 + W3X3 / W1 + W2 + W3 0A Therefore, Xcg = (0.010kg)(0m) + (0.060kg)(1.0m) + (0.040kg)(0.30) / (0.010kg) + (0.060kg) + (0.040kg) = 0.0720kg.m / 0.110 kg = 0.645 m I am not sure where I went wrong and why I have a higher number then the answer. Any help would be great! thank you!!!