Help solving non-linear ODE analytically

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Hi PF!

Anyone have any ideas for a solution to this $$0 = F F''+\left.2F'\right.^2+ xF' + F$$ where primes denote derivatives with respect to ##x##.
So far I have tried this $$0=\left( F F'\right)'+\left({xF}\right)'+\left.F'\right.^2$$

Which obviously failed. I also thought of this $$0 = F^2 F''+2F\left.F'\right.^2+ xFF' + F^2\\
= (F'F^2)' + (xF^2)'+xFF'$$
which also fails. Any ideas? I know an analytic solution exists, but how to derive it?
 
on Phys.org
joshmccraney said:
Hi PF!

Anyone have any ideas for a solution to this $$0 = F F''+\left.2F'\right.^2+ xF' + F$$ where primes denote derivatives with respect to ##x##.

F = -x is a particular solution. Look up how to do the "reduction of order" of a differential equation. (I say look it up, because I'd have to look it up myself before attempting to explain it.)
 
Stephen Tashi said:
F = -x is a particular solution. Look up how to do the "reduction of order" of a differential equation. (I say look it up, because I'd have to look it up myself before attempting to explain it.)
That's an idea, which is all I'm asking for. But ##-x## doesn't solve this. Comes close though.
 
joshmccraney said:
Hi PF!

Anyone have any ideas for a solution to this $$0 = F F''+\left.2F'\right.^2+ xF' + F$$ where primes denote derivatives with respect to ##x##.

I know an analytic solution exists, but how to derive it?

If [itex]F(x) = kx^2[/itex] then every term on the right is a constant times [itex]x[/itex]. You can then choose [itex]k[/itex] so that those constants sum to zero.
 
Thanks! I do know the exact solution is ##3(x^{1/3}-x^2)/10## but was wondering how to find this solution apart from guessing.
 

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