Help With Find The Cardinality of a Power Set of a Cartesian Product

daneault23
Messages
32
Reaction score
0

Homework Statement



Suppose that A and B are finite sets.
What is |P(AxB)|? Meaning what is the cardinality of the power set of a cartesian product of the sets A and B.


Homework Equations



|AxB|=|A| * |B| since A and B are finite sets
Power set of a set is the set of all subsets of that set, including the empty set and the set itself
There are 2^|A| subsets for a set A when A is finite


The Attempt at a Solution



Since A and B are finite sets, we have |AxB|=|A| * |B|. Now the power set of (AxB) is the set of all its subsets, including the empty set and the set AxB itself. Since A and B are both finite sets, there is also a finite number of subsets of (AxB). By letting C=AxB, there are exactly 2^|C| subsets. Thus |P(AxB)|=2^|AxB|=2^(|A| * |B|)

This is what I have.
 
Physics news on Phys.org
That's just fine.
 
I have a similar question asking what the |P(A)xP(B)| is. Can I ask that in this thread, or do I have to start another thread?
 
daneault23 said:
I have a similar question asking what the |P(A)xP(B)| is. Can I ask that in this thread, or do I have to start another thread?

You never HAVE to start another thread. It's usually recommended if the problem is unrelated but this one isn't. Ask here.
 
The question asks what is |P(A)xP(B)|. This is asking what is the cardinality of the cartesian product of the power set of A and power set of B. I'm having some trouble deciphering this.

I let C=P(A) and D=P(B). Then, |CxD|=|C| * |D| since once again A and B are both finite sets, meaning their respective power sets, C and D, are also finite sets.

So, |P(A)xP(B)|=2^C * 2^D

That is what I have.
 
No problem again. That's correct.
 
Dick said:
No problem again. That's correct.

Dick, are you saying that the syntax or form looks correct, or do you believe that is the correct answer?

So simplyifying it, it would be |P(A)xP(B)|=2^|C| * 2^|D|=2^2^|A| * 2^2^|B|
 
daneault23 said:
Dick, are you saying that the syntax or form looks correct, or do you believe that is the correct answer?

So simplyifying it, it would be |P(A)xP(B)|=2^|C| * 2^|D|=2^2^|A| * 2^2^|B|

No, I was reading too fast. It's 2^|A|*2^|B|. |C|=2^|A| and |D|=2^|B|. |CxD|=|C||D|.
 
Last edited:

Similar threads

  • · Replies 1 ·
Replies
1
Views
19K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
Replies
6
Views
8K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
18
Views
8K