Help with pie baking techniques

[manal950]

 

[Mark44]

You have a mistake on the next-to-last line. You have evaluated your antiderivative in the wrong order. Inside the parentheses you should have ln(sin($\pi/2$)) - ln(sin($\pi/6$)).

Also, the differential -- dx or du -- should appear in every step until you actually get the antiderivative.

When you make your substitution, that's when you should either change your limits of integration or at least make a note that the limits are values of x, not u. Here's what I mean:

$$ \pi \int_{x = \pi/6}^{\pi/2} \frac{du}{u}$$

By including "x = ..." in one of the limits of integration, that reminds you not to use them directly in the antiderivative that you get.

 

[manal950]

which line I got mistake is last line or what ?

 

[Mark44]

which line I got mistake is last line or what ?

I said which line in my last post.

You have a mistake on the next-to-last line. You have evaluated your antiderivative in the wrong order. Inside the parentheses you should have ln(sin($\pi/2$)) - ln(sin($\pi/6$)).

 

[SammyS]

...

Also, the differential -- dx or du -- should appear in every step until you actually get the antiderivative.

...

I pointed out this same omission in your previous thread.

 

[manal950]

Is the final answer is = 2.17 ?

 

[manal950]

Is the final answer will be = 2.17 ?

anyone help ?

 

[Mark44]

If you round to 2 decimal places, the answer is 2.18.