Hexadecimal number multiplication

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momentum
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I am trying to multiply hexadecimal numbers.

Here is what my book has given

Long multiplication of hexadecimal numbers: AFC4 times B9C, with partial products 83D30, 62DE4 and 78D6C (circled in red), summing to 7F88770 in a box.

Here is my solution
Handwritten long multiplication of hexadecimal numbers (AFC4)16 x (B9C)16 with partial products 8 3 D 3 0, 6 2 D E 4 and a red box around the row 6 F D 6 C.


book solution and my solution has differed in the red marked area.

which solution is correct?

am I doing anything wrong here? I get 6 F but book wrote 78 in that red marked area.

Need help with this part.

Thanks

 
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  • Long multiplication of hexadecimal numbers: AFC4 times B9C, with partial products 83D30, 62DE4 and 78D6C (circled in red), summing to 7F88770 in a box.
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  • Handwritten long multiplication of hexadecimal numbers (AFC4)16 x (B9C)16 with partial products 8 3 D 3 0, 6 2 D E 4 and a red box around the row 6 F D 6 C.
    0vDxRa0.png
    38.8 KB · Views: 1,104
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momentum said:
I am trying to multiply hexadecimal numbers.

Here is what my book has given

View attachment 225710
Here is my solution
View attachment 225711


book solution and my solution has differed in the red marked area.

which solution is correct?

am I doing anything wrong here? I get 6 F but book wrote 78 in that red marked area.

Need help with this part.

Thanks
The book's answer is correct for the part you circled. I didn't check anything else. I verified this using the calculator in Windows, in Programmer mode.
A possible reason for the number you got is that you didn't carry correctly.
 
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I get the book solution.
You have B * AFC4 = 6E000 + A500 + 840 + 2C and the 6E000 + A000 = 78000
 
Mark44 said:
A possible reason for the number you got is that you didn't carry correctly.

Yes. I made mistake in carry. corrected now.
Thanks. It helped a lot.