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Hg in U-shape tube, water is added. final h Hg?

  1. Aug 26, 2007 #1
    1. The problem statement, all variables and given/known data

    A U shaped container containing Hg at rest. 11.2 cm of water is added to the right side of container. How much does the Hg rise?


    2. Relevant equations

    p = p + [tex]\rho[/tex]gh



    3. The attempt at a solution
     
  2. jcsd
  3. Aug 26, 2007 #2

    berkeman

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    Staff: Mentor

    Welcome to the PF, locster! An important PF rule is that you need to show some of your initial work in order for us to offer you some tutorial help. What are your initial thoughts on how to approach this problem? Hint -- the water will not diffuse through the water to any great extent, so the water is only significant for its weight down on one surface of the mercury. Think of it as a teeter-totter with weights on the ends -- what is the balance condition?
     
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