Hg in U-shape tube, water is added. final h Hg?

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SUMMARY

The discussion centers on calculating the rise of mercury (Hg) in a U-shaped tube when 11.2 cm of water is added to one side. The relevant equation used is p = p + ρgh, where ρ represents the density of the fluids involved. The key insight is that the water's weight affects the mercury level without significant diffusion, creating a balance condition similar to a teeter-totter. The final height of Hg can be determined by equating the pressures exerted by the water and the mercury.

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Homework Statement



A U shaped container containing Hg at rest. 11.2 cm of water is added to the right side of container. How much does the Hg rise?


Homework Equations



p = p + \rhogh



The Attempt at a Solution

 
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Welcome to the PF, locster! An important PF rule is that you need to show some of your initial work in order for us to offer you some tutorial help. What are your initial thoughts on how to approach this problem? Hint -- the water will not diffuse through the water to any great extent, so the water is only significant for its weight down on one surface of the mercury. Think of it as a teeter-totter with weights on the ends -- what is the balance condition?
 

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