Hints for Proving n^5 = n (mod 10)

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Discussion Overview

The discussion revolves around proving that for any positive integer n, the expression n^5 and n have the same units digit in their base 10 representations, specifically that n^5 = n (mod 10). The scope includes mathematical reasoning and hints for proof techniques.

Discussion Character

  • Mathematical reasoning
  • Homework-related
  • Exploratory

Main Points Raised

  • One participant requests hints for proving that n^5 = n (mod 10).
  • Another participant suggests applying the Euler-Fermat theorem to the congruence mod 10.
  • A different participant expresses confusion about the Euler-Fermat theorem and asks for clarification on its application to the problem.
  • One participant provides a link to an external resource on the Euler-Fermat theorem and notes that it suffices to prove n^4 ≡ 1 (mod 10) for n coprime with 10.
  • Another participant reiterates the original problem and suggests that proving n^5 - n ≡ 0 (mod 10) can be approached by showing it is even and divisible by 5, mentioning that the first part is straightforward due to the factors involved.
  • This participant also proposes using mathematical induction to demonstrate the divisibility by 5, indicating it is not overly complex.

Areas of Agreement / Disagreement

Participants express various approaches and hints for the proof, but there is no consensus on a single method or resolution of the problem. Multiple viewpoints and techniques are presented without agreement on the best approach.

Contextual Notes

Some assumptions about the properties of numbers and their divisibility are implied but not explicitly stated. The discussion includes references to specific mathematical concepts that may require further clarification for some participants.

lil_luc
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Can anyone give me hints to how to prove this??

Prove that for any positive integer n, n^5 and n have the same units digit in their base 10
representations; that is, prove that n^5 = n (mod 10).

Thanks!
 
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What does the Euler-Fermat theorem tells you, when applied to a congruence mod 10?
 
I'm sorry, I'm still a bit lost. Can you please explain what the Euler-Fermat theorem is and how I can apply that to this problem?

Thanks
 
See the following link:

http://planetmath.org/encyclopedia/EulerFermatTheorem.html"

And notice that you only have to prove that:

[tex]n^{4}\equiv 1 \left(mod 10\right)[/tex]

For n coprime with 10.
 
Last edited by a moderator:
lil_luc said:
Can anyone give me hints to how to prove this??

Prove that for any positive integer n, n^5 and n have the same units digit in their base 10
representations; that is, prove that n^5 = n (mod 10).

Thanks!
This is equivalent to proving that n5 - n [itex]\equiv[/itex] 0 (mod 10)

You can show this by proving that n5 - n is even, and is divisible by 5.
The first part is easy, since two of the factors of n5 - n are n and n + 1, one of which has to be even for any value of n.
The second part, showing that n5 - n is divisible by 5 can be done by math induction, and isn't too tricky.
 

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