Homework SolutionCalculating Winch Power Requirement

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Homework Help Overview

The discussion revolves around calculating the power requirements for a winch used to raise and lower a lift with an undetermined mass and a counterweight. The lift's maximum speed is specified as 3 m/s, and it travels a total distance of 30 m. Participants are exploring the relationships between power, work, force, and acceleration in this context.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formulation of the power equation, with initial attempts involving power as a function of work and speed. There is a question about whether acceleration should be considered as gravitational acceleration. Some participants suggest alternative formulations for power and raise questions about the relationship between velocity and maximum speed.

Discussion Status

The discussion is active, with participants providing feedback on each other's equations and clarifying concepts. There is an acknowledgment of potential errors in the initial equations, and some participants are exploring different approaches to find acceleration. Guidance has been offered regarding the correct formulation of power.

Contextual Notes

Participants are working with an undetermined mass and are considering the implications of known and unknown variables in their equations. There is a focus on ensuring that the equations align with physical principles, particularly regarding forces and acceleration.

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Homework Statement


I need to write an equation to find the necessary power requirements of a winch used to raise and lower a lift of an undetermined mass and a counterweight that is half the mass of the lift. The maximum speed of the lift is 3m/s, and the lift travels a total of 30m.

Homework Equations


So far I have p=w*s where p is power, w is the work done and s is speed in m/s. Substituting the known value for speed I get p=w*3

Then I have w=f*d where f is force and d is distance in m. Substituting the value for d i get w=f*30

Next I have f=m*a where m is mass and a is acceleration in m/s squared. So I get a bit stuck on this part, should a be acceleration due to gravity? in which case I would have f=(m+1/2m)*9.81...?

Then I want to put all this into one formula, so I THINK this is right..
p={[(m+1/2m)*a]*d}*s

The Attempt at a Solution



which if i substitute in the correct values, the equation should look like this, with only the value of m being unknown...
P={[(m+m/2)*9.81]*30m}*3m/s

Is that the neatest way to set out the formula, and have I gotten the right formulas? I'm fairly sure I've done it right, just wanted to double check. Thanks in advance for having a read =)
 
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So far I have p=w*s where p is power, w is the work done and s is speed in m/s

The above equation is wrong.
It should be P = f*v, where f is the force applied and v is the velocity.
 
Okay thanks, so it should instead be - P=[(m+m/2)*9.81]*3 ?
I thought there would be a difference between the velocity and the maximum speed given for the lift.
 
Last edited:
One more question, if the value for M was known the answer to P would be in watts correct?
 
karmatic said:
One more question, if the value for M was known the answer to P would be in watts correct?

Yes.
 
karmatic said:
Okay thanks, so it should instead be - P=[(m+m/2)*9.81]*3 ?
I thought there would be a difference between the velocity and the maximum speed given for the lift.

The acceleration of the lift can be found as follows.

2mg - T = 2m*a...(1)
T - mg = m*a...(2)

Solvr these to equations to find a.
 

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