- #1
clairaut
- 72
- 0
I can't see the proof clearly.
Gradient [f(tx,ty)] dot
<d/dt (tx) , d/dt (ty)> =
d/dt [f(tx,ty)] = n * t^(n-1) * [f(x,y)]
I don't see how the t^(n-1) term disappears.
HELP
Gradient [f(tx,ty)] dot
<d/dt (tx) , d/dt (ty)> =
d/dt [f(tx,ty)] = n * t^(n-1) * [f(x,y)]
I don't see how the t^(n-1) term disappears.
HELP