MHB Homogeneous linear ODEs with Constant Coefficients

Click For Summary
Homogeneous linear ordinary differential equations (ODEs) with constant coefficients can be expressed in the form ay' + by = 0, leading to the solution y' = -b/a * y, where k = -b/a. The general solution involves exponential functions, but trigonometric functions like y = sin x can also be solutions for specific equations such as y'' + y = 0. The discussion highlights that as long as certain boundary conditions are not applied, the trivial solution y = 0 is valid. Additionally, the solution can be represented as a combination of sine and cosine functions, indicating the flexibility in the types of solutions available for these ODEs. Understanding these concepts is crucial for solving homogeneous linear ODEs effectively.
oasi
Messages
14
Reaction score
0
do you have a idea about it?can you help me

http://img17.imageshack.us/img17/1156/18176658.png
 
Physics news on Phys.org
oasi said:
do you have a idea about it?can you help me

http://img17.imageshack.us/img17/1156/18176658.png

For example, take $ay' + by = 0$. Solving for y' yields
$$
y' = -\frac{b}{a}y = ky
$$
where k = -b/a.

The only nontrivial function whose derivative is a constant multiple of itself is an exponential function.
 
But $y = \sin x$ could work. For example,

$y'' + y = 0$

has as one solution $y = \sin x$.
 
Jester said:
But $y = \sin x$ could work. For example,

$y'' + y = 0$

has as one solution $y = \sin x$.

As long as the boundaries aren't $y'(0) = 0$ and $y'\left(\frac{\pi}{2}\right) = 0$ then y = 0. :)

But $y = A\sin x + B\cos x = e^0\left(A\sin x + B\cos x\right)$ is also a solution of the non boundary value problem.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
2K
  • · Replies 36 ·
2
Replies
36
Views
5K