How a laser resonator generates the standing wave?

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Discussion Overview

The discussion revolves around how optical laser resonators generate standing waves. Participants explore the conditions necessary for this phenomenon, the role of mirror distance, and the implications of different resonator designs.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • Some participants propose that the length of the resonator must be a multiple of half the wavelength for standing waves to form (L=k*(lambda/2)).
  • Others suggest that the frequency of the light adjusts itself to fit a whole number of wavelengths within the resonator, although the mechanism of this adjustment is questioned.
  • A participant seeks clarification on the conditions under which an optical resonator generates standing waves, referencing a definition from Wikipedia.
  • One participant distinguishes between different types of resonators, asserting that while a Fabry-Perot interferometer can create standing waves, a ring resonator does not.
  • Another viewpoint emphasizes that standing waves may not be necessary, but rather a specific wavelength for interaction is required, allowing for multiple photon journeys within the resonator.

Areas of Agreement / Disagreement

Participants express differing views on the necessity and conditions for standing waves in laser resonators, with no consensus reached on the implications of different resonator types.

Contextual Notes

There are unresolved questions regarding the specific mechanisms of frequency adjustment and the definitions of standing waves in various resonator configurations.

Basov
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Hi, guys. I'm interrest in the question about how optical (laser) resonator can generates the standing wave? As i know, there is a condition that the resonator base (lenght between two mirrors) should be multiple to the length of the wave. (L=k*(lamda/2)). But in practice no one never measures the distance between the mirrors of the resonator when creating the laser system. So i would like to ask you, how actually laser resonator can generates the standing wave without the measuring the distance between two mirrors?
 
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Basov said:
Hi, guys. I'm interrest in the question about how optical (laser) resonator can generates the standing wave? As i know, there is a condition that the resonator base (lenght between two mirrors) should be multiple to the length of the wave. (L=k*(lamda/2)). But in practice no one never measures the distance between the mirrors of the resonator when creating the laser system. So i would like to ask you, how actually laser resonator can generates the standing wave without the measuring the distance between two mirrors?
The frequency will adjust itself slightly so that a whole number of wavelengths fit in the resonator.
 
How can "frequency adjust itself"? How this process called?
 
Ok, i specify the question. Can you write the condition in which the optical resonator generates the standing wave? According to the wikipedia "an optical cavity is an arrangement of mirrors that forms a standing wave". Is it mean that any pair of 2 or more mirrors (which forms different types of the optical resonators) gives the standing wave in the output beam?
 
I almost realize the idea of generating the standing wave in optical resonator. The main concept is that the reflected and falling light beams must propagates towards each other. So the fabry-perot interferometer makes the standing wave, but ring resonator is don't make the SW. Am I right??
 
I understand it this way. You don't need standing waves, but you need a certain wavelength for interaction at each end. This allows for multiple journeys back and forth which increases the chances of photons escaping at that wavelength.
(Just noticed... my 1000th post!)
 
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