How can I accurately set up a tri-quadratic equation for curve fitting in Excel?

  • Thread starter Thread starter mattskie
  • Start date Start date
Click For Summary
To set up a tri-quadratic equation for curve fitting in Excel, the user has successfully implemented a bi-quadratic model and is now attempting a tri-linear equation. The current equation, x^2 + x*y + x*z + y^2 + y*z + z^2 + b, shows initial accuracy but fails with subsequent data points. The user questions the correctness of their approach and references a source that provided inaccurate results. They seek guidance on whether the fitting curve should follow a different form, such as ax^2 + by^2 + cz^2. Accurate setup and validation of the equation are crucial for improved curve fitting results.
mattskie
Messages
10
Reaction score
0
Hey,

So I am trying to do a tri-quadratic curve fit (linear regression) in excel. I have successfully completed a bi-quadratic, and it is of the form:
x+x^2+y+y^2+x*y+b (b is calculated by LINEST in excel)

My attempt at a tri-linear was:
x^2+x*y+x*z+y^2+y*z+z^2+b (b is calculated by LINEST in excel)

This equation was fairly accurate for my first few data points in the 4-curve family of curves I am attempting to curve fit, but after that the accuracy plummets.

I am assuming I am on the right track with this, as I attained some initial accuracy, but this equation isn't 100% because I can see it failing. Any/all help appreciated.

Note: I attempted to use the equation on http://www.rmi.ge/~kade/LecturesT.Kadeishvili/MathEconomics/Term3/Week3QuadraticLEC.pdf
but it gave an extremely erroneous solution.
 
Physics news on Phys.org
Shouldn't the fitting curve be:
ax^2 + by^2 + cz^2 + etc.?
 
The standard _A " operator" maps a Null Hypothesis Ho into a decision set { Do not reject:=1 and reject :=0}. In this sense ( HA)_A , makes no sense. Since H0, HA aren't exhaustive, can we find an alternative operator, _A' , so that ( H_A)_A' makes sense? Isn't Pearson Neyman related to this? Hope I'm making sense. Edit: I was motivated by a superficial similarity of the idea with double transposition of matrices M, with ## (M^{T})^{T}=M##, and just wanted to see if it made sense to talk...

Similar threads

  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 6 ·
Replies
6
Views
4K
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
Replies
3
Views
2K