How can i derive this Gibbs energy equation?

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SUMMARY

The Gibbs free energy for an electrochemical cell is defined by the equation G = -nFE, where G represents Gibbs free energy, n is the number of moles of electrons, F is Faraday's constant, and E is the cell potential. The relationship between standard state Gibbs free energy (ΔGθ) and the equilibrium constant (K) is established through the equation ΔGθ = -nFEθ, where Eθ is the standard cell potential. At equilibrium, the free energy change (ΔG) is zero, leading to the conclusion that K equals the reaction quotient Q. Thus, the derived expression relating standard state cell potential and equilibrium constant is ΔGθ = -RT ln(K).

PREREQUISITES
  • Understanding of Gibbs free energy and its equations
  • Familiarity with electrochemical cells and cell potential
  • Knowledge of the relationship between equilibrium constants and reaction quotients
  • Basic principles of thermodynamics in chemical reactions
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  • Study the derivation of the Nernst equation for electrochemical cells
  • Explore the relationship between Gibbs free energy and spontaneity of reactions
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Chemistry students, electrochemists, and anyone studying thermodynamics in relation to chemical reactions will benefit from this discussion.

lioric
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Homework Statement



For an electrochemical cell Gibbs free energy is is given by G=-nFE
Gibbs free energy for a reaction at any moment in time and standard state free energy is given by G=Go + RT lnQ

Derive an expression relating standard state cell potential and equilibrium constant for a reaction


Homework Equations



ΔG=-nFE and ΔG=ΔGθ + RT lnQ

The Attempt at a Solution



I actually don t have an idea
But i m guessing that i have to mix both equations up since ΔG is common and then I'm totally clueless
 
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What will be the value of ΔG and Q at equilibrium? And if Eθ were the standard cell potential, how would it be related to ΔGθ?
 
Q would be K G would be-nFE
 
lioric said:
Q would be K G would be-nFE

Q would be K. You are right there. However, ΔGθ=nFEθ (you have already written so). Now to the part which is key to solving this,

When you have the reactants and products at equilibrium, what do you think the net free energy change for the whole process ( forward +backward reactions) is?

Say A \Leftrightarrow B. For the forward reaction, let ΔG be the free energy change. What will be the free energy change for the reverse reaction? So what will be net free energy change (free energy change for forward reaction + free energy change for the reverse reaction)?

If you figure this out, the answer to the original question just pops out.:wink:
 

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